a road roller takes 500 complete revolutions to level a ground . find the area of the ground if the diameter of the road roller is 1.26m and l is 1 m
Answers
Answered by
9
Answer:
Solution:-
Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m
In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = 2πrh
= 2*22/7*0.42*1
Area of the road in one revolution = 2.64 sq m
Therefore, in 750 revolutions, the area of the road = 2.64*750
= 1980 sq m
Answer.
Step-by-step explanation:
Similar questions