A road roller takes 500 complete revolutions to move once over to level a road. Find the area of
the road if the diameter of a road roller is 84 cm and length is 1 m.
Answers
Answer:
Given :
Diameter of a road roller = 84 cm
Length = 1 m
Road roller takes 500 complete revolution to move once over to leave a road.
To find :
Area of the road
According to the question,
⇝ Radius = 84 ÷ 2 = 42 cm
Note :
We have change 42 cm into m. So, the value is 0.42 m
\sf : \implies{Curved \: surface \: area \: of \: cylinder = 2 \pi rh }:⟹Curvedsurfaceareaofcylinder=2πrh
\begin{gathered} \\ \end{gathered}
\sf : \implies{2 \times \dfrac{22}{7} \times 0.42 \: m \times 1 \: m}:⟹2×722×0.42m×1m
\begin{gathered} \\ \end{gathered}
\sf : \implies { \dfrac{18.48}{7} \: {m}^{2} }:⟹718.48m2
\begin{gathered} \\ \end{gathered}
{ \underline{ \boxed { \bf \red{ : \implies{2.64 \: {m}^{2} }}}}} \: \bigstar:⟹2.64m2★
So, the area of road in one revolution is 2.64 m².
Now,
➞ Area of road in 500 revolution = 2.64 × 500
➞ Area of road in 500 revolution = 1320 m²
\therefore {\underline{ \sf{Area \: of \: road \: in \: 500 \: revolution \: is \: 1320 \: {m}^{2} }}}∴Areaofroadin500revolutionis1320m2