Math, asked by rajangadkary, 3 months ago

. A road roller takes 500 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m.​

Answers

Answered by xxsilentkillerxx67
5

Answer:

Area of road =750× area covered in 1 revoluation

=750× lateral surface area of cylinder

=750×2πrh

Given, d=84cm⇒r=42cm→

100

42

m

h=1m

=750×2×

7

22

×

100

42

×1

=

100

1500×132

=1980m

2

Step-by-step explanation:

please mark my answer as brainliest please please please.........

Answered by MuTeGlitZzz
20

Given:

⇒D=84 cm,l=1m

⇒r=42cm

⇒Area of road covered in 1 revolution =2πrl =2×

7

22

×42×1=

100

264

sq m

⇒Area of road covered in 750 revolution = 750×(

100

264

) =1980 sq m

Its not the solution of ur ques.....

jst put 500 in place of 750

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