Question

. A road roller takes 500 complete revolutions to move once over to level a ground. Find the area of the ground in m2, if the diameter of the road roller is 80 cm and length is 1m 40 cm.

Answer 1

Area of road =750× area covered in 1 revoluation

=750× lateral surface area of cylinder

=750×2πrh

Given, d=84cm⇒r=42cm→

100

42

m

h=1m

=750×2×

7

22

×

100

42

×1

=

100

1500×132

=1980m

2

If the road roller takes 750 revolution to move once over to level a ground.and the diameter was 84cm and length was 1m.

Answer 2

Answer:

Area of road =1760 M²

Step-by-step explanation:

Length =Height = 1 m 40 cm

= 140 cm

Diameter = 80 cm

Radius = 80/2 =40 cm

Curved Surface Area of cylinder = 2πrh

$2 \times \frac{22}{7} \times 40 \times 140 \\ = 22 \times 2 \times 40 \times 20 \\ = 22 \times 2 \times 800 \\ = 22 \times 1600 \\ = 35200cm^{2}$

500 complete round =

$500 \times 35200 \\ = 17600000cm^{2}$

In m² =

$\frac{17600000}{10000} = 1760$

Area of the road =1760 m²