A road roller takes 500 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 41 cm and its length ia 1 m. (use π = 22/7)
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Answer:
1 revolution = 2\pi rh2πrh
r\ =\ \frac{84}{2\ }cm\r =
2
84
cm
= 42cm
h = 1m = 100cm
CSA = 2\times\frac{22}{7}\times42\times1002×
7
22
×42×100
= 26400 cm\ ^2cm
2
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