Math, asked by wildkiller1508, 3 months ago

A road roller takes 500 complete revolutions to move once over to level a road.
Find the area of the road if the diameter of a road roller is 42 cm and its length is 1 m.
(use n =
22/7)

Answers

Answered by hdewangan1278
2

Answer:

660m^2 Answer

Step-by-step explanation:

Diameter = 42cm

Radius = 42/2 = 21cm

length = 100cm

C.S.A. = 2πrh = 2×22/7×21×100

= 13,200cm^2

Area of road = C.S.A. × Revolutions

= 13,200 × 500

= 6,600,000cm^2

In meter = 6,600,000/10000

= 660m^2 Answer

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