Question

A Road roller takes 500 revolutions to
level the ground. Find area of
ground, if diameter of roller is 80 cm and
length 1 m.​

Answer 1

Step-by-step explanation:

Length of roller = 1m = 100cm

Circumference of roller = π x D = 22/7 X 84 =  264 cm

Length of road = 264 x 750 = 198000 cm

Width of road = length of roller = 100 cm

Area of road = 198000 x 100 = 19,800,000 cm² or 1980 m

                                                  OR

Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m

In one revolution, the road roller will cover an area equal to its lateral surface area.

So, in one revolution the area of the road covered = 2πrh

= 2*22/7*0.42*1

Area of the road in one revolution = 2.64 sq m

Therefore, in 750 revolutions, the area of the road = 2.64*750

= 1980 sq m

Answer 2

Answer will be 1980 sq .cm

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