A road roller takes 600 complete revolutions to move once over to level a road. Find the area of the road (in sqm) if the diameter of a road roller is 84 cm and length is 3m.
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Answer:
4,752 m²
Step-by-step explanation:
Road roller is a Right Circular Cylinder. The area covered by 1 revolution of road roller is nothing but the curved surface area (c.s.a) of the cylinder.
The c.s.a of cylinder = 2πrh
r= D/2 = 84/2 = 42cm
L = 3m = 300 cm
= 2πrh
= 2 × (22/7) × 42 × 300
= 79200 cm²
So, the roller revolve once, it would cover an area of 79,200 cm². If it revolves 600 times, it would cover
= 600 × 79200
= 47,520,000 cm²
= 4,752 m² (Area of the road)
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