A road roller takes 630 revolutions to make once over to a level a road. Find the area of the road if the diameter of the road roller is 54cm and length is 1m
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Your answer is 1069.2m^2
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Area of road =750× area covered in 1 revoluation
=750× lateral surface area of cylinder
=750×2πrh
Given, d=84cm⇒r=42cm→10042m
h=1m
=750×2×722×10042×1
=1001500×132
=1980m2
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