A road roller takes 750 complete resolution to move once over to level a road. Find the area of the road if the diameter of the road roller is 84 CM and it's length is 1 m
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Answer:
Diameter of roller= 84 cm.
Radius of roller= 84/2=42 cm
Curved surface area of roller= 2πrh= 2×22/7 ×42×100 sq. cm= 26400 sq. cm
Area covered in 1 rev. = 26400 sq. cm
Area covered in 750 rev. =(750×26400) sq. cm= 19800000sq.cm= 1980 sq. m
Answer:- Area of road= 1980 sq. m
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Diameter of road roller = 84cm
Therefore radius = 84/2 = 42cm = 0.42m
Curved surface area of cylinder = 2 x pi x radius x height
= 2 x 22/7 x 0.42 x 1
= 44 x 0.06
= 2.64m.sq
Therefore area of road = 750 x 2.64
= 1980m.sq
Therefore radius = 84/2 = 42cm = 0.42m
Curved surface area of cylinder = 2 x pi x radius x height
= 2 x 22/7 x 0.42 x 1
= 44 x 0.06
= 2.64m.sq
Therefore area of road = 750 x 2.64
= 1980m.sq
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