a road roller takes 750 complete revolutions to move once over to level Erode find the area of the road if the diameter road roller is 84cm and length is 1 m
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Length of roller = 1m = 100cm
Circumference of roller = π x D = 22/7 X 84 = 264 cm
Length of road = 264 x 750 = 198000 cm
Width of road = length of roller = 100 cm
Area of road = 198000 x 100 = 19,800,000 cm² or 1980 m²
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Golda Ace
Solution:-
Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m
In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = 2πrh
= 2*22/7*0.42*1
Area of the road in one revolution = 2.64 sq m
Therefore, in 750 revolutions, the area of the road = 2.64*750
= 1980 sq m
hope it helps you!!!!
$hreya
Circumference of roller = π x D = 22/7 X 84 = 264 cm
Length of road = 264 x 750 = 198000 cm
Width of road = length of roller = 100 cm
Area of road = 198000 x 100 = 19,800,000 cm² or 1980 m²
4.5
152 votes
THANKS
676
Comments Report
Golda Ace
Solution:-
Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m
In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = 2πrh
= 2*22/7*0.42*1
Area of the road in one revolution = 2.64 sq m
Therefore, in 750 revolutions, the area of the road = 2.64*750
= 1980 sq m
hope it helps you!!!!
$hreya
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