Question

A road roller takes 750 complete revolutions to move once over to level a room
area of the road, if the diameter of the road roller is 84 cm and length is im.​

Answer 1

Step-by-step explanation:

Given,

Literal surface area of the road roller

$= \frac{2 \times 22}{7} r42$

$= 100$

$(r = \frac{84}{2} = 42cm)$

$= 26400 {cm}^{2}$

Area covered by the roller in 750 complete revolutions

$= 26400 \times 750 {cm}^{2}$

$= \frac{19800006}{10000} = {m}^{2} = 1980 {m}^{2}$

Hence, the area of road = 1980m²

Answer 2

Answer:

Heyy

Step-by-step explanation:

Literal surface area of the road roller

= \frac{2 \times 22}{7} r42

= 100

(r = \frac{84}{2} = 42cm)

= 26400 {cm}^{2}

Area covered by the roller in 750 complete revolutions

= 26400 \times 750 {cm}^{2}

= \frac{19800006}{10000} = {m}^{2} = 1980 {m}^{2}

Hence, the area of road = 1980m²

Hope it helps ❤️