a road roller takes 750 complete revolutions to move once over to level a road find the area of the road if the diameter of a road roller is 84cm and length is 1m
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4
diameter of road roller = 84 cm
radius of road roller = 84/2 cm= 42 cm = 0.42 m
length of road roller = 1m
area of road roller = 2×pi×radius×height
= 2×(22/7)×0.42×1 m^2
[Note : Length can be taken as height as the cylindrical roller is not standing upright]
= 2×22×0.06×1 m^2
= 44×0.06 cm^2
= 2.64 m^2
Now area of road = 2.64 m^2 × 750
= 1980 cm^2
Hence area of road = 1980 m^2 or 198000 cm^2
radius of road roller = 84/2 cm= 42 cm = 0.42 m
length of road roller = 1m
area of road roller = 2×pi×radius×height
= 2×(22/7)×0.42×1 m^2
[Note : Length can be taken as height as the cylindrical roller is not standing upright]
= 2×22×0.06×1 m^2
= 44×0.06 cm^2
= 2.64 m^2
Now area of road = 2.64 m^2 × 750
= 1980 cm^2
Hence area of road = 1980 m^2 or 198000 cm^2
karthik3684:
the answer is 1980
Answered by
1
Length of roller = 1m = 100cm
Circumference of roller = π x D = 22/7 X 84 = 264 cm
Length of road = 264 x 750 = 198000 cm
Width of road = length of roller = 100 cm
Area of road = 198000 x 100 = 19,800,000 cm² or 1980 m²
hope it helps!!
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