A road roller takes 750 complete revolutions to move once over to level the road .find the area of the road if the diameter of a roadroller is 84 cm and lenght is 1 m.
Answers
Answered by
1622
Length of roller = 1m = 100cm
Circumference of roller = π x D = 22/7 X 84 = 264 cm
Length of road = 264 x 750 = 198000 cm
Width of road = length of roller = 100 cm
Area of road = 198000 x 100 = 19,800,000 cm² or 1980 m²
Circumference of roller = π x D = 22/7 X 84 = 264 cm
Length of road = 264 x 750 = 198000 cm
Width of road = length of roller = 100 cm
Area of road = 198000 x 100 = 19,800,000 cm² or 1980 m²
Answered by
807
Solution:-
Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m
In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = 2πrh
= 2*22/7*0.42*1
Area of the road in one revolution = 2.64 sq m
Therefore, in 750 revolutions, the area of the road = 2.64*750
= 1980 sq m
Answer.
Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m
In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = 2πrh
= 2*22/7*0.42*1
Area of the road in one revolution = 2.64 sq m
Therefore, in 750 revolutions, the area of the road = 2.64*750
= 1980 sq m
Answer.
Similar questions