Question

a road roller takes 800 complete revolutions to move once over to level a road find the area of the road if the diameter of the road roller is 98 cm and lenght is 1 m

Answer 1

Heyy mate ❤✌✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️⤵️⤵️

1 m = 100 cm.

Circumference of Roller = pie × Diameter.

= 22/7 × 98

= 22 × 14

= 308cm.

Length of road = 800 × 308

= 246, 400cm.

Width of Roller = length of roller = 100cm.

Therefore ,

Area of road = l × b

= 246400 × 100

= 24640000 cm^2.

=2464 m^2.
✔✔✔

Answer 2

$\large \tt AHOY!! \:$

ATQ, a road roller takes 800 complete revolutions to move once over to level a road.

given :-

diameter = 98cm

therefore radius = 98/2 = 49cm

length (height) = 1m = 100cm

we know that a road roller is basically cylindrical. so we can use the formula of CSA of cylinder.

CSA of the road roller = 2πrh

= 2 × 22/7 × 49 × 100

= 44 × 7 × 100

= 30800cm²

now we have to find the area of the road if it takes 800 complete revolution to level the road.

simply multiply the CSA with 800 and u will get ur answer.

= 800 × 30800

= 24640000cm²

hence, the area of the road is 24640000cm².

solving for the question which u posted in comment section...

the walls and the ceiling of a hall 20m × 16m × 10m are to be painted from each can of paint 130m² of area is painted. how many cans are required to paint the room?

ans :-

dimensions of hall is given = 20m × 16m × 10m

length = 20m, breadth = 16m and height = 10m

first we have to find the area of four walls and the ceiling.

so we will use the formula CSA + 1 base

CSA + 1 base of the hall = 2h(l + b) + lb

= 2 × 10(20 + 16) + (20 × 16)

= 20(36) + 320

= 720 + 320

= 1040m²

ATQ, one can of paint can paint 130m²

therefore no. of cans required = 1040/130

= 8

hence, 8 cans of paint are required.

solving for next question u posted in comment section..

• if the volume of a cylinder is 3080cm³ and the base radius is 7cm. find the height of the cylinder also find a) curved surface area b) total surface area.

given volume of the cylinder = 3080cm³

radius = 7cm

we know the formula for the volume of a cylinder. that is πr²h

therefore πr²h = 3080cm³

=> 22/7 × 7 × 7 × h = 3080cm³

=> 22 × 7 × h = 3080cm³

=> 154 × h = 3080cm³

=> h = 3080/154

=> h = 20cm

the height of the cylinder is 20cm.

a) curved surface area of the cylinder = 2πrh

= 2 × 22/7 × 7 × 20

= 44 × 20

= 880cm²

b) TSA of the cylinder = 2πr(h + r)

= 2 × 22/7 × 7(20 + 7)

= 44 × 27

= 1188cm²

$\large \tt HOPE \: THIS \: HELPS!!$