a road take 750 revolutions to more once to level a raod .if the diameter of road roller is 84 cm and length is 1 m.find the area of raod
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The road roller is cylinder....
radius = 84/2 =42 cm
length(h)= 1m = 100 cm..
Lateral surface area = 2πrh
=>2×22/7 ×42×100 = 2×22×6×100= 26400cm^3
Area levelled by roller in 1 revolution = 26400 cm^3
Area levelled by roller in 750 revolutions=
750×26400/100×100 =15×32 = 1980m^2
(Here, i divided by 100×100 to convwrt it into m^2)
Thus, the required area of the road =1980 m^2
Hope it helps u...
if yes, mark brainliest...
have a great day ahead...
@TeraBhalaHo
radius = 84/2 =42 cm
length(h)= 1m = 100 cm..
Lateral surface area = 2πrh
=>2×22/7 ×42×100 = 2×22×6×100= 26400cm^3
Area levelled by roller in 1 revolution = 26400 cm^3
Area levelled by roller in 750 revolutions=
750×26400/100×100 =15×32 = 1980m^2
(Here, i divided by 100×100 to convwrt it into m^2)
Thus, the required area of the road =1980 m^2
Hope it helps u...
if yes, mark brainliest...
have a great day ahead...
@TeraBhalaHo
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