Question

A road takes 750 complete revolutions to move once over to level a road . Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m.

Answer 1

In this question, It is given that,

Diameter of Roller = 84 cm
Radius of Roller = 42 cm = 42/100 m
Height = 1 m

$= > \: area \: covered \: = 2 \pi \: r \: h$

$= > area \: covered \: = \: 2 \times \frac{22}{7} \times \frac{42}{100} \times 1$

$= > area \: covered \: = \frac{1848}{7 \times 100}$

$= > area \: covered \: = \frac{264}{100}$

Now,

Area covered in 750 Revolution,

$= > area \: = 750 \times \frac{264}{100} \: {m}^{2}$

$= > \: area \: = (75 \times 26.4) \: {m}^{2}$

$= > \: area \: = 1980 \: {m}^{2}$


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