A road which is 7 m wide surrounds a circular park whose circumference is 352 m. Find the area of the road.
Answers
Answered by
30
Heya !!
Let the radius of the park be r m.
Then,
Its circumference = 2πr m.
2πr = 352
2 × 22/7 × r = 352
r = 56 m.
Thus,
Inner radius = 56 m.
Outer radius = (56+7) = 63 m.
Area of road = π [ (63)² - (56)² ]
=> 22/7 × ( 63 + 56 ) ( 63 - 56 ) m²
=> (22/7 × 119 × 7) m²
=> 2618 m²
Let the radius of the park be r m.
Then,
Its circumference = 2πr m.
2πr = 352
2 × 22/7 × r = 352
r = 56 m.
Thus,
Inner radius = 56 m.
Outer radius = (56+7) = 63 m.
Area of road = π [ (63)² - (56)² ]
=> 22/7 × ( 63 + 56 ) ( 63 - 56 ) m²
=> (22/7 × 119 × 7) m²
=> 2618 m²
Answered by
11
Given= breath of Road(b)=7m
Circumferemce of Circular park=352m
sol= circumference=2r1
352m=2 x 22/7 x r1
r1=352m x 1/2 x7/22
r1=56m
Radius of circle including road(r2))= 56+7=63
Area of road= (r12 – r22)
= 22/7x(632 -562)
=2618 m2
Circumferemce of Circular park=352m
sol= circumference=2r1
352m=2 x 22/7 x r1
r1=352m x 1/2 x7/22
r1=56m
Radius of circle including road(r2))= 56+7=63
Area of road= (r12 – r22)
= 22/7x(632 -562)
=2618 m2
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