A road which is 7m wide surrounds a circular park whose circumferernce is 352m.Find surface area of road
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Given 2pir = 352m.
r = 352 * 7/44 = 56
R = 56 + 7 = 63
Area of road = pi (R^2 - -r^2)
= 22/7((63)^2 - (56)^2)
= 22/7 * 833
= 2618.
Hope this helps!
r = 352 * 7/44 = 56
R = 56 + 7 = 63
Area of road = pi (R^2 - -r^2)
= 22/7((63)^2 - (56)^2)
= 22/7 * 833
= 2618.
Hope this helps!
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