A road whose width is 7 m surrounds a circular path whose circumference is 352 m. Find the area of the road.
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Answered by
2
Given:
Circumference of a circular park= 352 m
Width of a road = 7 m
Circumference = 2πr
352 = 2 ×( 22/7)× r
352×7 = 44r
r = (352×7)/44 = 8 × 7 = 56 m
Inner radius of the park (r) = 56 m
Outer radius of the Park including the road (R )= width + r
R = 7 + 56 = 63 m
R = 63 m
Area of the road = π(R² - r²)
= π(R+r) (R - r) [a² - b² = (a-b)(a-b)]
= 22/7 (63+56)(63-56)
= 22/7 × 119 × 7
= 22 × 119
Area of the road= 2618 m²
Hence, the Area of the road is 2618 m².
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Answered by
1
Answer:
Step-by-step explanation:
Radius of path =r
2πr=352
r=56
Area of road =π(R+r)(R-r)
=π×(63+56)×7=2618
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