Question

A rock dropped on the moon will increase its speed from 0m/s to 8.15 m/s in about 5 seconds if you were standing on the moon measuring the rocks motion what would you measure for the magnitude of its acceleration

Answer 1

Answer:

Acceleration =1.63 m/s^2

Explanation:

Use the formula

$a = \frac{v - u}{t}$

Where

u(initial velocity) =0m/s

v(final velocity) =8.15m/s

time=5s

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Answer 2

The magnitude of acceleration is $1.63\ m/s^2$.

Explanation:

We have,

Initial speed, u = 0

Final speed, v = 8.15 m/s

Time, t = 45 s

The magnitude of acceleration is given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{8.15-0}{5}\\\\a=1.63\ m/s^2$

So, the magnitude of acceleration is $1.63\ m/s^2$.

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Acceleration

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