A rock hits the ground at a speed of 10 m
leaves a hole 25 cm deep. The magnitude of th
(assumed) uniform deceleration of the rock is
(1) 100 m/s2
(2) 150 m/s2
(3) 250 m/s2
(4) 200 m/s2
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I think a is the right answer
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Answer:
Explanation:
a = (v^2 - u^2)/2s = {0 -(10)^2}/(2*1/4) = 200 m/s^2
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