Question

A rock is dropped into a canyon that is 0.65 km deep. Determine the time it takes the rock to hit the bottom of the canyon?

Answer 1

Answer:

≈ 11.5 seconds

Explanation:

S (distance)  = 0.65 km = 650 m

g (gravitational acceleration) = 9.8m/s²

S = ut + 1/2at²

650 = 0 + 1/2(9.8)(t²)

650 = 4.9 (t²)

t² = 650/4.9 ≈ 132.65

Therefore, t ≈ 11.5 seconds

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