A rock is thrown downward from a bridge that is 12 m above a small creek. The rock has an initial velocity of 3.0 m/s downward. What is the velocity of the rock just before it hits the water?
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v^2=u^2+2as
=9+2×10×12
=249
V=√249
=9+2×10×12
=249
V=√249
alismanggalisp8v52b:
Wrong. The answer is 16m/s down
oops sorry mate. I forgot to √ . Thanks for your help
welcome follow me for more answers
sure will do :)
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