Question

A rock is thrown horizontally from the top of a building with an initial speed of v=10.1m/s. If it lands d=57.1m from the base of the building, how high is the building? a)200m b)156.6m c)198m d)56m​

Answer 1

Answer:

A rock is projected from the edge of the top of a building with an initial velocity of 19.6 m/s at an angle of 31 degrees above the horizontal

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Answer 2

Answer:

b)156.6m

Explanation:

if we throw horizontally it means angle with horizontal is 0°.

so, h= u sin¢ *t +1/2gt^2

h=1/2 gt^2. (sin¢=sin0°=0)

t=√(2h/g)

and range, R = u*t

R=u√(2h/g)

for horizontal projection

so,

57.1=10.1√(2h/9.8)

57.1/10.1=√2h/9.8

{(5.65)^2} *9.8/2=h

h=5.65*5.65*4.9

h=156.4 ~= 156.6m