Physics, asked by Warrenw, 1 year ago

A rock is thrown straight up and reaches a height of 8 m. How long was the rock in the air?

Answers

Answered by harsh1726
0

Answer:

6 sec

Explanation:

Answered by Siddharthjatt
1

H = (u^2)(sinx)^2/g

8 = (u)^2 / 10

80 = (u)^2

u = 4√5

t = usinx / g

t = 4√5 / 10

t = 2/√5

t = 0.894s

PLEASE MARK THE ANSWER AS BRAINLIEST

Similar questions