Physics, asked by kalika59, 9 months ago

A rock is thrown straight up from the edge of a cliff. The rock reaches the maximum
height of 15 m above the edge and then falls down to the bottom of the cliff 35 m
below the cliff. What is the displacement of the rock?​

Answers

Answered by bishansingh786
6

Answer:

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Answered by SrijanB2022
3

Answer:

The displacement of the rock is 35 metres in the downward direction

Explanation:

What is displacement?

Displacement is defined as the shortest straight-line distance between the initial and starting points of an object.
Displacement cannot be negative (direction can be negative with respect to the initial point, but not the value of displacement)

Refer to the diagram attached below.

Here, the height of the cliff is 35m.
So, the initial point or starting point of the rock is 35m above the bottom of the cliff (or sea level).
Now, the rock is thrown upwards at first and it covers 15m upright and then falls right at the bottom of the cliff.
Since displacement means the shortest distance between the initial and final points, so we will neglect the first 15m upright motion of the rock and calculate the displacement from the edge of the cliff, i.e., the point from where it was thrown/released.

Thus, the displacement of the rock is 35 metres in the downward direction.

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