A rock of mass 200kg is dropped from a height of 200m. What is the potential energy and kinetic energy at 2seconds
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Answered by
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Explanation:
pe=1/2mgh
pe=1/2*200*9.8*200
pe=196000
ke=1/2m*vsquare
ke=1/2*200*(100)square. v=200/2=100m/s
ke=1000000
Answered by
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Answer:
PE = 392000J KE =38416 J
Explanation:
PE = mgh
= 200x9.8x200
= 392000J
= 3.92x0^5 J
v=u+gt
=0 +9.8x2
=19.6m/s
KE =1/2mv^2
= 1/2x 200x 19.6^2
= 38416 J
=3.84 x10^4 J
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