A rock weighing 2000N is to be displaced with an effort of magnitude 1200N using a lever. What should be the length of the lever if the possible load arm is only 30cm from the pivot?
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let the length of the lever be x
then the other part has a length of 30-x
for lever problems, we take that torque produced by each force should become 0
so, 2000(30-x)=1200(x)
5(30-x)=3(x)
150-5x=3x
8x=150
x=150/8cm=18.75cm
|--------------------o--------------------------------------|
| 30-x x |
2000N. 1200N
you can see this diagram for the concept of zeo torque.
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