A rock weighs 1400 N in air, has an apparent weight of 900 N when submerged in fresh water (998kg/m^3).The volume in m^3 of the rock is (g = 9.8 m / s2 )
Answers
Answered by
31
According to given data
weigh in air = 1400 N
Apparent weigh = 900 N
Density = 998 Kg/m³
Solution
Now,according to formula :
Loss of water displaced = loss of weight
1400-900 = V x 998 x 9.8
500 = 9780.4 x V
900 = 1400 - V x 998 x 9.8
9780.4 V = 500
V = 500/9780.4
V = 0.0051 m³
Answered by
15
Loss of weight= 1400-900=500N
Density p=998kg/m3
Loss of weight=Loss of water displaced
500=pVg
V= 0.05m3
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