Question

A Rock weighs 1400 Newton in air ,has an Apparent weight of 900 Newton when submerged in freshwater(998 kg/m^3).The volume (in m^3) of the rock is??
(g=9.8 m/s^2)

Answer 1

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Formula to be used :
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=> buoyancy force

= $\bf \: weight \: \: of \: \: immersed \: \: in \: \: water$


$= > force = \bf \: mass \times gravity \\ \\ = > volume = \bf \: mass \div density$
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=> Weight of rock in air =$\bf \: 1400 \: \: N$

=> Weight of rock in water = $\bf \: 900 \: \: N$


=> buoyancy force =(1400 - 900)N

=$\bf \: 500 \: \: N$


=>Weight of water dispersed=$\bf \: 500 \: \: N$


=> gravity (g) = $\bf \: 9.8 \: \: m \: {s} ^{-2}$


=> density (D) = $\bf \: 998\: \:$ kg/m³


$= > mass = \bf\frac{force}{gravity} = \frac{500}{9.8} = 51.02 \: kg$

=> Volume dispersed

$= \frac{mass}{density} = \bf \: \frac{51.02}{998} = 0.051 \: {m}^{3}$
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Answer 2

Answer:

Answer is 0.051msq..........