Question

A rock weighs 25.7 N in air and 21.8 N in water. What is the buoyant force
of the water​

Answer 1

Answer:

Explanation:

buoyant force=Downward  Force in normal condition -Downward Force in Water

buoyant force= 25.7 N-21.8 N=3.9N

Answer 2

Answer:

3.9 N is the buoyant force of the water.

Explanation:

Given,A rock weighs 25.7 N in air and 21.8 N in water.

So, Weight of the rock in air is 25.7 N

Weight of the rock in water is 21.8 N

By Archimedes Principle,

$B = ρ × V × g$

Where ρ and V = object density and volume respectively .

g = gravitational acceleration.

Magnitude of buoyant force acting on the rock = (Downward force in air - Downward force in water)

= $(25.7 - 21.8) = 3.9 \: N$