Physics, asked by drsathiya118, 1 year ago

a rocket consumes 50kg fuel per second the exhaust speed of a gases w.r.t rocket 3 km/s the force exerteds on the rocket by the fuel is.

Answers

Answered by BrainlyWriter
9

\bold{Answer:-}

F = 150000 N

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Given—

°Consumption of fuel = 50 Kg/sec

°Exhausted speed of gases w.r.t rocket = 3 km/sec = 3000 m/s

To find

°The force exerted on the rocket by fuels = ?

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Step-By-Step Explaination

Overall momentum of the system is conserved.

Therefore, change in momentum of the rocket will be equal to that of the fuel.

Change in momentum of the fuel will be

\bf\Large{\triangle\:mv = 50\times\:3000}

\bf\Large{\triangle\:mv = 150000}

Hence, change in momentum of the rocket will also be:

\bf\Large{\triangle\:P =150000 }

We know that Thrust Force

\Large\bold{\boxed{\boxed{F=\frac{\triangle\:P}{\triangle\:t} }}}

Here \bf\Large{\triangle\:t \:is\:unit\:sec}

Therefore Force exerted by fuel is 150000 N

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