Question

a rocket drawing has the measures as given in the figure. find its area​

Answer 1

HOPE THIS ANSWER HELPED

MARK AS BRAILIEST

Answer 2

Answer:

Area of the rocket = 3500 square cm.

Step-by-step explanation:

In the given figure,

The area of the rocket = Area of trapezium + Area of Rectangle + Area of Triangle

Now,

Area of Trapezium,

$T=\frac{1}{2}(Sum\ of\ parallel\ sides)\times height$

So,

$T=\frac{1}{2}(30+50)\times 20=800\ cm^{2}$

Area of Rectangle,

$R=Length \times \ Width$

So,

$R=80\times 30=2400\ cm^{2}$

Also,

Area of Triangle,

$T=\frac{1}{2}\ base\times height$

So,

$S=\frac{1}{2}\times 30\times 20=300\\S=300\ cm^{2}$

So,

Area of Rocket is,

$Area\ of\ rocket=T+R+S=800+2400+300\\Area\ of\ rocket=3500\ cm^{2}$

Therefore, the area of the rocket = 3500 square cm.