Question

a rocket fired vertically up travels with an acceleration of 10 metre per second square the acceleration ceases at the end of 60 second from the start what is the maximum height reached by the rocket​

Answer 1

acceleration, a= 10m/s²

time = 60s

initial velocity, u = 0m/s (rest)

maximum height, h= ?

We know that,

a = v - u/t

=> 10 = v/60

=> v = 600 m/s

Using equation of motion:

2gh = v² - u² (let g= 10m/s²)

=> 20h = 360000 - 0

=> h = 360000/20

=> h = 18000m Or 18km

You can also use the equation:

h = ut² + gt²/2

Answer 2

Answer:

S = 18km

Explanation:

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