Question

. A rocket flies 10 km vertically, then 20 km at an angle of
15° to the vertical and finally 60 km at an angle of 26° to the
vertical. Calculate the vertical height of the rocket at the end
of the third stage.​

Answer 1

Answer:

The tricky part of this problem is two-fold:

1) The set-up is slightly vague if you don't realize that the angles are set-up with respect to the vertical, ending up with the resulting flight path looking similar to a left hand curved inward.

2) The trigonometric ratio used to determine the height from the second and third stage is not cosine but sine due to the angle placement.

Therefore, the answer is: 10km + 20km*sin(15) + 60km*sin(26) = approx. 41.479 km vertical height

Step-by-step explanation:

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Answer 2

Answer:

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