Question

A rocket initially at rest on the ground lifts o vertically with a constant acceleration of 2.0*10^1 meters per second^2. How long will it take the rocket to reach an altitude of 9.0* 10^3 meters?

Answer 1

à sign simply indicates multiplication operation. Thus, we have the following given: a = acceleration = -2*101 = -202 m/s^2 (Note: negative sign because it opposes the gravitational force) d = distance/altitude = 9*103 = 927 meters v = initial velocity = 0 m/s To solve for the time, we have first the working fomula d = v*t - 0.5*a*t^2 where: t = time Substituting, 927 = 0*t-0.5*(-202)*t^2 t = 3.03 seconds ANSWER: t = 3.03 sec