a rocket is fired an ascends with constant vertical acceleration 10m/s^2 for one minute.Its is exhausted and it continues as a free particle.find the maximum altitude reached?
Answers
Answered by
5
s=ut+1/2at^2
=1/2(10)(60)^2
=18000m
=18km
=1/2(10)(60)^2
=18000m
=18km
Naddu4u:
no it isn't the correct answer
it is...
they have given me the options a)18km b)36km c)72
18000m=18km
sorry dude
36 is the correct ans but i just want to know the method
ohh okay
Answered by
33
Height reached in 1 min =( 10 x 60 x 60)÷2
=18000m
velocity after 1 min =√2gh = √2x10x18000
=√360000 =600m/s
so, u=600, v=0, a=-10, h=?
by Newton's 3rd law
0 = 360000 -2×10×h
h=18000m
so , max altitude = 18000 +18000=36 km
=18000m
velocity after 1 min =√2gh = √2x10x18000
=√360000 =600m/s
so, u=600, v=0, a=-10, h=?
by Newton's 3rd law
0 = 360000 -2×10×h
h=18000m
so , max altitude = 18000 +18000=36 km
heyy how we are getting the acceleration (-10)
please explain evrything clearly
that is gravitt
gravity
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