Question

A rocket is fired vertically from the ground with a resultant vertical acceleration of 10m/s2

. The

fuel is finished in 1 min and it continues to move up. What is the maximum height reached?​

Answer 1

Answer:

initial velocity=0

let height goes with acceleration =10m/s^2 be {h}

Time=1min=60sec

h=1/2at^2

H=0.5×10×60×60=18000m

V=at

V=10×60=600m/s

H=distance travels without fuel

There will apply {g=a}

H=v^2/2g

H=600×600/2×10 {let g=10m/s^2}

H=18000m

Total distance travels={h+H}

=>18000+18000=36000=36km