A rocket is fired vertically upwards with an acceleration 10 m/s2 . To what maximum heights would the rocket rise if its fuel gets exhausted in 1 min?
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Answer:
Explanation:
S=ut= 1/2at^2
S= 1/2
(10) (30^2)
=4500m
v^2+u^2=2as
v=300m/s
now after fuel is consumed
a=−10
v=0
v=u−gt
t=30s
totaltime=30+30=60s
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