A rocket is going vertically upward. After 10 seconds,its engine was stopped.Find the maximum height at which it can reach.
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Explanation:
h= ut+1/2gt^2 , Therefore Max. height of rocket after 10 seconds = 0×10 + 1/2 × (-10) ×10×10 =-1000/2 =-500 m, but this value can not be negative so taking positive value 500m.
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