Question

a rocket is in shape of cone mounted on right circular cylinder their common Base diameter is 8cm the height of cylinder and conceal shapes are 6cm and 3cm respectively find the volume of the rocket

Answer 1

Answer:

Step-by-step explanation:

u multiply 3 times 6 and get 18

Answer 2

Curved surface area of cone = πrl
= 22/7*2.5*8
= 440/7
= 62.86 sq m
Curved surface area of cylinder = 2πrh
= 2*22/7*2.5*21
= 330 sq m
Area of the base circle of the cylinder = πr²
= 22/7*2.5*2.5
= 19.64 sq m
Total surface area of rocket = 62.85 + 330 + 19.64
= 412.5 sq m
Volume of cylinder = πr²h
= 22/7*2.5*2.5*21
= 412.5 cu m
Now 
h² = 8² - (2.5)²
h² = 64 - 6.25
h² = 57.75
h = √57.75
h = 7.6 m
Volume of the cone = 1/3πr²h
= 1/3*22/7*2.5*2.5*7.6
= 49.76 cu m
Total volume of rocket = 412.5 + 49.76
= 462.26 cu m


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