A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=-16x^2+160x+51
Answers
Answered by
51
The time that the rocket will hit the ground is 12.87 seconds.
Given:
The rocket is launched from a tower \(y=-16x^2+199x+90\).
Similar questions