Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.

y=-16x^2+201x+132

Answer 1

$\huge\pink{A}\blue{N}\red{S}\purple{W}\orange{E}\green{R}$

628foot