Physics, asked by rohth5996, 10 months ago

A rocket is launched normal to the surface of earth, away from the Sun, along the line joining the Sun and
the Earth. The Sun is 3 x 10⁵ times heavier than the Earth and is at a distance 2.5 x10⁴ times larger than the
radius of the Earth. The escape velocity from Earth’s gravitational field is vₑ = 11.2 km s⁻¹
. The minimum initial (v????) required for the rocket to be able to leave the Sun-earth system is closest to
(Ignore the rotation and revolution of the Earth and the presence of any other planet)
[A] v???? = 22 km s⁻¹
[B] v???? = 42 km s⁻¹
[C] v???? = 62 km s⁻¹
[D] v???? = 72 km s⁻¹

Answers

Answered by Anonymous
2

Answer:

B ?

please mark as brainliest

Answered by mrsria
1

Answer:

Sorry mate !!!!!!! I don't know the answer but thanks for the free 15 points

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