A rocket is launched upward with a acceleration of 10m/s^2.After 1min the fuel has finished.So what would be the maximum height the rocket will reach?
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S=Vit+1/2at^2
S=1/2at^2
S=1/2(10)(60)×(60)
S=1/2(10)3600
S=5(3600)
S=18000m
S=1/2at^2
S=1/2(10)(60)×(60)
S=1/2(10)3600
S=5(3600)
S=18000m
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