Question

A rocket is launched vertically from the surface of the earth with an initial velocity 8km/s. How far above the surface the earth would it go?( Ignore the air resistance, take radius of earth=6400km and g=9.8ms^-2)​

Answer 1

Answer:

it will fall down

Explanation:

it will fall down to earth because the escape velocity required is 11m/s

Answer 2

Explanation:

The rocket will not leave the earth As the minimum velocity i.e,ESCAPE VELOCITY, required to leave the earth is 11km/s.... And since it is moving with initial velocity of 8km/s, the rocket will not leave the earth and hence will come back...

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