a rocket is moving up with a velocity v. if the velocity is tripled, then what will be the ratio of two kinetic energies?
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KE=1/2mv²
therefore, KE is directly proportional to v²
thus....
KE₁=1/2mv²
KE₂=1/2m(3v)²
=1/2m(6v²)
=6(1/2mv²)
=6KE₁
therefore the ratio is=1:6
therefore, KE is directly proportional to v²
thus....
KE₁=1/2mv²
KE₂=1/2m(3v)²
=1/2m(6v²)
=6(1/2mv²)
=6KE₁
therefore the ratio is=1:6
Dakshansh:
you have written (3v)^2 = 6v^2 but actually it is 9v^2
oh...sorry by mistake....
sorry...
thr=e ratio is=1:9...
the*
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