Question

A Rocket is moving up with velocity v. if the velocity of the rocket is tripled, what will be the ratio of kinetic energies?​

Answer 1

let mass be M

original velocity = V

new velocity = 3V

original KE = 1/2 x M x V^2

New KE = 1/2 x M x(3 V)^2

ratio

= original KE / New KE

= (1/2 x M x V^2)/(1/2 x M x (3V)^2)

= V^2 / 9 V^2

=1/9

Hope it helps

Answer 2

$\underline{\underline{\mathfrak{\large {Answer:-}}}}$

$\bf{\red{We\: know \: kinetic\: energy = \frac{1}{2} m {v}^{2} }}$

$\bf{\blue{If \: the \: velocity \: is \: tripled ,\: kinetic \:energy}}$

$\bf{\orange {= \frac{1}{2} m (3{v}^{2})}}$

$\bf{\purple{= \frac{9}{2} mv ^{2} }}$

$\bf{\green{Kinetic \: energy \: increases \: by \: 9 \: times}}$