Question

A rocket is moving vertically upward with speed 500 kilometre per hour it is rejecting product of combustion with speed 2000 kilometre per hour with respect to find out actual product of combustion.​

Answer 1

Explanation:

$\sf \bold{Given} \\ \\ \sf{Speed \: of \: moving \: rocket = 500 kilometre \: per \: hour} \\ \\ \sf{Speed \: of \: ejection \: product \: combustion = 2000 kilometre \: per \: hour \: with \: respect \: to \: itself} \\ \\ \sf \large\bold{A.T.Q.} \\ \\ \sf \bold{By \: Concept \: of \: relative \: speed} \\ \\ \sf=> Vr = Vj + VP \\ \\ \sf=> 2000 = 500 + Vp \\ \\ \sf=> Vp = 1500 km/ h \\ \\ \large \sf \bold{Hence} \\ \\ \sf \underline{Speed \: of \: combustion \: product \: is \: 1500 \: km \: per \: hour.}$

Answer 2

Answer:

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Speed of vertically moving rocket (Vj) =500km/hr

Speed of ejecting product of combustion(Vr) =2000km/hr

Let actual product of combustion be Vp.

As,

Vr=Vj+Vp

2000km/hr=500km/hr+Vp

2000-500=Vp

1500 km/hr=Vp